Hi all
Here is a little idea I've been having for a while now, and wanted to see what you think...
(sorry for jumping from one topic to another, but I'm just trying to make up for all the time I've lost and get on with more than one thing at the same time)
Basically, I wouldn't mind the idea of having
skyline diffusers at the rear of the CR. There - I admit it - I quite like the visual interest they add
I know
Stuart in particular is never keen in advising their use in small rooms (for good reasons !)… but I have a plan
…. well at least I think I do
… and would be great to have some feedback if possible.
Right - the plot is to extend (on both sides) the frame I built for the air con unit, until it reaches the hangers trap framing
Simo plan_1.jpg
fill the entire cavity with insulation (a la
superchunk !)
Simo plan_2.jpg
and then position the
skyline diffusers there (with screws or using a
french cleat mounting method, in order to be able to remove them if I'll see that their contribution is not beneficial acoustically, thus leaving me with just more straight absorption... which I seem to understand is never a bad think
).
Simo plan_3.jpg
Simo plan_4.jpg
The info I've collected and put together so far in my various journeys through the forum is that as a general rule:
numeric-based diffusers must be away from your ears a distance
at least 3 times (
others say 7 times!) the wavelength of the lower frequency they are tuned to.
(not forgetting that diffusers are also effective an octave below the lowest tuned frequency !).
This is to avoid the so called "
lobbing" problem, corresponding in an uneven spread of reflected energy (in both space and time).
Now, in my control room the distance between the sitting spot and the frame where I was considering of placing the diffusers is around 2.4m.
Simo Studio section.jpg
So: 2.4m / 7 = 0.343 m =>
34.3 cm
This means (always following the theory) that 34.3 cm is the wavelength of the lower frequency the diffuser should be tuned to.
Well, actually that happens to be precisely the wavelength of 1KHz:
from: "
V = f λ " where:
V(
speed of sound (m/sec)),
f (
frequency (Hz),
λ (
wavelength)
λ = V / f = 343 / 1000 = 0.343 m =>
34.3 cm
If the above is correct, it means (always in theory) that I should be ok by installing up there diffusers tuned @ 1KHz (or perhaps 2KHz to be safe?), without having an uneven spread of reflected energy ???
Anyone? …Stuart, are you there
(please destroy me gently ) ?
Thanks
Simo
